engine displacement

sycam_steve

New member
Re: engine displacement

PI * r^2 * stroke * # of cylinders where r is 1/2 the bore diameter

3.14 * 2^2 * 3.50 *6 =~262 cubic inches where 2 is 1/2 the bore which is 4.00 stroke is 3.50.

Thanks,

Steven Sebastian
BSME Kettering University (GMI/EMI) 93'
 

gkrcr882

SyTyless......for now!
Re: engine displacement

1 liter = 61.02 cubic inches



The 4.3L V6 has the standard 5.7L 4.00" bore and 3.48" stroke.
 
Re: engine displacement

using the bore diameter, calculater the area of the cylinder and mulitply that times the stroke. that is the displacement of one cylinder, multiply that times the number of cylinders.

the syclone is 262 cubic inches
 

gkrcr882

SyTyless......for now!
Re: engine displacement

A little more food for thought:

Compression Ratio:


V1+V2+V3+V4 / V2+V3+V4

V1= Bore x Bore x Stroke x .7854
V2= Bore x Bore x crushed gasket thickness x .7854
V3= Bore x Bore x deck clearance x .7854
V4= combustion chamber volume x .061


*V4 will be changed when using domed or dished pistons. Add to the combustion chamber volume when using dished pistons, subtract the dome volume when using domed pistons. All combustion chamber volumes are in CC's
 

Don W.

Stab it and steer it
Re: engine displacement

It's hidden in the above. Bore X Bore X .7854 X Stroke X (number of cylinders)
 
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